1411224140831 has 2 divisors, whose sum is σ = 1411224140832. Its totient is φ = 1411224140830.

The previous prime is 1411224140813. The next prime is 1411224140863. The reversal of 1411224140831 is 1380414221141.

Together with previous prime (1411224140813) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (1411224140863) can be obtained adding 1411224140831 to its sum of digits (32).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411224140831 is a prime.

It is a super-2 number, since 2×1411224140831² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411224140731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705612070415 + 705612070416.

It is an arithmetic number, because the mean of its divisors is an integer number (705612070416).

Almost surely, 2^{1411224140831} is an apocalyptic number.

1411224140831 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411224140831 is an equidigital number, since it uses as much as digits as its factorization.

1411224140831 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 32.

Adding to 1411224140831 its reverse (1380414221141), we get a palindrome (2791638361972).

The spelling of 1411224140831 in words is "one trillion, four hundred eleven billion, two hundred twenty-four million, one hundred forty thousand, eight hundred thirty-one".