Base | Representation |
---|---|
bin | 1100110101011101101100… |
… | …0100101100000011101100 |
3 | 1211222011012100121120201122 |
4 | 3031113123010230003230 |
5 | 3322210143102203300 |
6 | 50003131513400112 |
7 | 2654414310201650 |
oct | 315273304540354 |
9 | 54864170546648 |
10 | 14112643006700 |
11 | 4551158074857 |
12 | 16bb15b709038 |
13 | 7b4a7cba1034 |
14 | 36b0ac68aa60 |
15 | 19718006dc85 |
hex | cd5db12c0ec |
14112643006700 has 72 divisors (see below), whose sum is σ = 36206229007200. Its totient is φ = 4671771471360.
The previous prime is 14112643006699. The next prime is 14112643006747. The reversal of 14112643006700 is 760034621141.
14112643006700 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 347581745 + ... + 347622344.
Almost surely, 214112643006700 is an apocalyptic number.
14112643006700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14112643006700 is an abundant number, since it is smaller than the sum of its proper divisors (22093586000500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14112643006700 is a wasteful number, since it uses less digits than its factorization.
14112643006700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 695204139 (or 695204132 counting only the distinct ones).
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 14112643006700 its reverse (760034621141), we get a palindrome (14872677627841).
The spelling of 14112643006700 in words is "fourteen trillion, one hundred twelve billion, six hundred forty-three million, six thousand, seven hundred".
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