141132434443100 has 36 divisors (see below), whose sum is σ = 306546032720088. Its totient is φ = 56399766408000.

The previous prime is 141132434443097. The next prime is 141132434443129. The reversal of 141132434443100 is 1344434231141.

141132434443100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×141132434443100³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 664985486 + ... + 665197685.

It is an arithmetic number, because the mean of its divisors is an integer number (8515167575558).

Almost surely, 2^{141132434443100} is an apocalyptic number.

141132434443100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141132434443100 is an abundant number, since it is smaller than the sum of its proper divisors (165413598276988).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141132434443100 is a wasteful number, since it uses less digits than its factorization.

141132434443100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1330184246 (or 1330184239 counting only the distinct ones).

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 141132434443100 its reverse (1344434231141), we get a palindrome (142476868674241).

The spelling of 141132434443100 in words is "one hundred forty-one trillion, one hundred thirty-two billion, four hundred thirty-four million, four hundred forty-three thousand, one hundred".