Base | Representation |
---|---|
bin | 10100100010011001100… |
… | …010110010001000011010 |
3 | 11222220212200112220210022 |
4 | 110202121202302020122 |
5 | 141110343234232440 |
6 | 3000204235150442 |
7 | 203651646106031 |
oct | 24423142621032 |
9 | 4886780486708 |
10 | 1411325305370 |
11 | 4a45a33838a2 |
12 | 1a9635ba5422 |
13 | a311a04c4b6 |
14 | 4c446799718 |
15 | 26aa255acb5 |
hex | 148998b221a |
1411325305370 has 32 divisors (see below), whose sum is σ = 2831389473600. Its totient is φ = 503358126336.
The previous prime is 1411325305339. The next prime is 1411325305409. The reversal of 1411325305370 is 735035231141.
It is a super-3 number, since 3×14113253053703 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1411325305370.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 218468180 + ... + 218474639.
It is an arithmetic number, because the mean of its divisors is an integer number (88480921050).
Almost surely, 21411325305370 is an apocalyptic number.
1411325305370 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1411325305370 is an abundant number, since it is smaller than the sum of its proper divisors (1420064168230).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1411325305370 is a wasteful number, since it uses less digits than its factorization.
1411325305370 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 436942862.
The product of its (nonzero) digits is 37800, while the sum is 35.
The spelling of 1411325305370 in words is "one trillion, four hundred eleven billion, three hundred twenty-five million, three hundred five thousand, three hundred seventy".
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