141143205523421 has 2 divisors, whose sum is σ = 141143205523422. Its totient is φ = 141143205523420.

The previous prime is 141143205523417. The next prime is 141143205523423. The reversal of 141143205523421 is 124325502341141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112708182520921 + 28435023002500 = 10616411^2 + 5332450^2 .

It is a cyclic number.

It is not a de Polignac number, because 141143205523421 - 2² = 141143205523417 is a prime.

Together with 141143205523423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141143205523423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70571602761710 + 70571602761711.

It is an arithmetic number, because the mean of its divisors is an integer number (70571602761711).

Almost surely, 2^{141143205523421} is an apocalyptic number.

It is an amenable number.

141143205523421 is a deficient number, since it is larger than the sum of its proper divisors (1).

141143205523421 is an equidigital number, since it uses as much as digits as its factorization.

141143205523421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 141143205523421 its reverse (124325502341141), we get a palindrome (265468707864562).

The spelling of 141143205523421 in words is "one hundred forty-one trillion, one hundred forty-three billion, two hundred five million, five hundred twenty-three thousand, four hundred twenty-one".