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1412142415511 is a prime number
BaseRepresentation
bin10100100011001010001…
…111110011111010010111
311222222222122002102011212
4110203022033303322113
5141114031424244021
63000421304452035
7204011130324242
oct24431217637227
94888878072155
101412142415511
114a4982640833
121a982377a01b
13a321a413319
144c4c30da259
1526aee16285b
hex148ca3f3e97

1412142415511 has 2 divisors, whose sum is σ = 1412142415512. Its totient is φ = 1412142415510.

The previous prime is 1412142415469. The next prime is 1412142415543. The reversal of 1412142415511 is 1155142412141.

It is an a-pointer prime, because the next prime (1412142415543) can be obtained adding 1412142415511 to its sum of digits (32).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1412142415511 - 26 = 1412142415447 is a prime.

It is a super-2 number, since 2×14121424155112 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1412142415561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706071207755 + 706071207756.

It is an arithmetic number, because the mean of its divisors is an integer number (706071207756).

Almost surely, 21412142415511 is an apocalyptic number.

1412142415511 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412142415511 is an equidigital number, since it uses as much as digits as its factorization.

1412142415511 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6400, while the sum is 32.

Adding to 1412142415511 its reverse (1155142412141), we get a palindrome (2567284827652).

The spelling of 1412142415511 in words is "one trillion, four hundred twelve billion, one hundred forty-two million, four hundred fifteen thousand, five hundred eleven".