Base | Representation |
---|---|
bin | 1100110110011110010110… |
… | …1000011010101011011111 |
3 | 1212000210222222212220122121 |
4 | 3031213211220122223133 |
5 | 3323001220000422142 |
6 | 50015122110323411 |
7 | 2655600400263631 |
oct | 315474550325337 |
9 | 55023888786577 |
10 | 14130000014047 |
11 | 4558554704325 |
12 | 17025a44b9567 |
13 | 7b65b7b31c98 |
14 | 36bc7793ca51 |
15 | 197848c65c67 |
hex | cd9e5a1aadf |
14130000014047 has 2 divisors, whose sum is σ = 14130000014048. Its totient is φ = 14130000014046.
The previous prime is 14130000013949. The next prime is 14130000014051. The reversal of 14130000014047 is 74041000003141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14130000014047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14130000014087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065000007023 + 7065000007024.
It is an arithmetic number, because the mean of its divisors is an integer number (7065000007024).
Almost surely, 214130000014047 is an apocalyptic number.
14130000014047 is a deficient number, since it is larger than the sum of its proper divisors (1).
14130000014047 is an equidigital number, since it uses as much as digits as its factorization.
14130000014047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 14130000014047 its reverse (74041000003141), we get a palindrome (88171000017188).
The spelling of 14130000014047 in words is "fourteen trillion, one hundred thirty billion, fourteen thousand, forty-seven".
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