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1413003140429 is a prime number
BaseRepresentation
bin10100100011111101100…
…011001101110101001101
312000002012121200202210112
4110203331203031311031
5141122312300443204
63001042533045405
7204041351344316
oct24437543156515
95002177622715
101413003140429
114a5284488141
121a9a23a86865
13a33268380ca
144c56555160d
1526b4e9d226e
hex148fd8cdd4d

1413003140429 has 2 divisors, whose sum is σ = 1413003140430. Its totient is φ = 1413003140428.

The previous prime is 1413003140411. The next prime is 1413003140431. The reversal of 1413003140429 is 9240413003141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1398235300900 + 14767839529 = 1182470^2 + 121523^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1413003140429 is a prime.

Together with 1413003140431, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1413003140395 and 1413003140404.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1413003140729) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706501570214 + 706501570215.

It is an arithmetic number, because the mean of its divisors is an integer number (706501570215).

Almost surely, 21413003140429 is an apocalyptic number.

It is an amenable number.

1413003140429 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413003140429 is an equidigital number, since it uses as much as digits as its factorization.

1413003140429 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 32.

The spelling of 1413003140429 in words is "one trillion, four hundred thirteen billion, three million, one hundred forty thousand, four hundred twenty-nine".