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141312000013351 is a prime number
BaseRepresentation
bin100000001000010111000011…
…100100000011010000100111
3200112100021222020201211111021
4200020113003210003100213
5122010223434000411401
61220313500412352011
741523312044301226
oct4010270344032047
9615307866654437
10141312000013351
11410320a0014042
1213a23266a75607
1360b088397574b
1426c7774498cbd
151150cb1b862a1
hex8085c3903427

141312000013351 has 2 divisors, whose sum is σ = 141312000013352. Its totient is φ = 141312000013350.

The previous prime is 141312000013267. The next prime is 141312000013411. The reversal of 141312000013351 is 153310000213141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141312000013351 - 223 = 141311991624743 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141312000016351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70656000006675 + 70656000006676.

It is an arithmetic number, because the mean of its divisors is an integer number (70656000006676).

Almost surely, 2141312000013351 is an apocalyptic number.

141312000013351 is a deficient number, since it is larger than the sum of its proper divisors (1).

141312000013351 is an equidigital number, since it uses as much as digits as its factorization.

141312000013351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 141312000013351 its reverse (153310000213141), we get a palindrome (294622000226492).

The spelling of 141312000013351 in words is "one hundred forty-one trillion, three hundred twelve billion, thirteen thousand, three hundred fifty-one".