14133114030 has 32 divisors (see below), whose sum is σ = 38765113344. Its totient is φ = 3230426016.

The previous prime is 14133114001. The next prime is 14133114031. The reversal of 14133114030 is 3041133141.

14133114030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 14133113988 and 14133114006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14133114031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33650062 + ... + 33650481.

It is an arithmetic number, because the mean of its divisors is an integer number (1211409792).

Almost surely, 2^14133114030 is an apocalyptic number.

14133114030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14133114030 is an abundant number, since it is smaller than the sum of its proper divisors (24631999314).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14133114030 is a wasteful number, since it uses less digits than its factorization.

14133114030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67300560.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 14133114030 its reverse (3041133141), we get a palindrome (17174247171).

The spelling of 14133114030 in words is "fourteen billion, one hundred thirty-three million, one hundred fourteen thousand, thirty".