Base | Representation |
---|---|
bin | 1000001110111000010… |
… | …0100101010101011101 |
3 | 111112001201101112210021 |
4 | 2003232010211111131 |
5 | 4304123340214011 |
6 | 144550134512141 |
7 | 13134562534552 |
oct | 2035604452535 |
9 | 445051345707 |
10 | 141433132381 |
11 | 54a88352772 |
12 | 234b1805651 |
13 | 1044c771418 |
14 | 6bb9ac6a29 |
15 | 3a2b95d471 |
hex | 20ee12555d |
141433132381 has 2 divisors, whose sum is σ = 141433132382. Its totient is φ = 141433132380.
The previous prime is 141433132331. The next prime is 141433132409. The reversal of 141433132381 is 183231334141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 103705897156 + 37727235225 = 322034^2 + 194235^2 .
It is a cyclic number.
It is not a de Polignac number, because 141433132381 - 217 = 141433001309 is a prime.
It is a super-2 number, since 2×1414331323812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141433132331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70716566190 + 70716566191.
It is an arithmetic number, because the mean of its divisors is an integer number (70716566191).
Almost surely, 2141433132381 is an apocalyptic number.
It is an amenable number.
141433132381 is a deficient number, since it is larger than the sum of its proper divisors (1).
141433132381 is an equidigital number, since it uses as much as digits as its factorization.
141433132381 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20736, while the sum is 34.
The spelling of 141433132381 in words is "one hundred forty-one billion, four hundred thirty-three million, one hundred thirty-two thousand, three hundred eighty-one".
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