14143341443500 has 96 divisors (see below), whose sum is σ = 31146482727360. Its totient is φ = 5610249216000.

The previous prime is 14143341443401. The next prime is 14143341443509. The reversal of 14143341443500 is 534414334141.

It is a self number, because there is not a number n which added to its sum of digits gives 14143341443500.

It is not an unprimeable number, because it can be changed into a prime (14143341443509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 95097196 + ... + 95245804.

It is an arithmetic number, because the mean of its divisors is an integer number (324442528410).

Almost surely, 2^{14143341443500} is an apocalyptic number.

14143341443500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14143341443500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15573241363680).

14143341443500 is an abundant number, since it is smaller than the sum of its proper divisors (17003141283860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14143341443500 is a wasteful number, since it uses less digits than its factorization.

14143341443500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150212 (or 150200 counting only the distinct ones).

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 14143341443500 its reverse (534414334141), we get a palindrome (14677755777641).

The spelling of 14143341443500 in words is "fourteen trillion, one hundred forty-three billion, three hundred forty-one million, four hundred forty-three thousand, five hundred".