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1414613621021 is a prime number
BaseRepresentation
bin10100100101011101100…
…010101101100100011101
312000020100212002122211212
4110211131202231210131
5141134112041333041
63001510423154205
7204126305245106
oct24453542554435
95006325078755
101414613621021
114a5a30568037
121aa1b32a5965
13a35223a03c3
144c6793b33ad
1526be60a18eb
hex1495d8ad91d

1414613621021 has 2 divisors, whose sum is σ = 1414613621022. Its totient is φ = 1414613621020.

The previous prime is 1414613620991. The next prime is 1414613621023. The reversal of 1414613621021 is 1201263164141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 837600192025 + 577013428996 = 915205^2 + 759614^2 .

It is a cyclic number.

It is not a de Polignac number, because 1414613621021 - 210 = 1414613619997 is a prime.

It is a super-2 number, since 2×14146136210212 (a number of 25 digits) contains 22 as substring.

Together with 1414613621023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1414613621023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707306810510 + 707306810511.

It is an arithmetic number, because the mean of its divisors is an integer number (707306810511).

Almost surely, 21414613621021 is an apocalyptic number.

It is an amenable number.

1414613621021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414613621021 is an equidigital number, since it uses as much as digits as its factorization.

1414613621021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 32.

Adding to 1414613621021 its reverse (1201263164141), we get a palindrome (2615876785162).

The spelling of 1414613621021 in words is "one trillion, four hundred fourteen billion, six hundred thirteen million, six hundred twenty-one thousand, twenty-one".