Base | Representation |
---|---|
bin | 1100110111111100101001… |
… | …1000000000011111001000 |
3 | 1212010020100001212000200022 |
4 | 3031333022120000133020 |
5 | 3323410040002001100 |
6 | 50034505533400012 |
7 | 2660454561160415 |
oct | 315771230003710 |
9 | 55106301760608 |
10 | 14155312531400 |
11 | 4568263994257 |
12 | 1707489639008 |
13 | 7b8ac00298c1 |
14 | 36d1995d710c |
15 | 19832b0bae85 |
hex | cdfca6007c8 |
14155312531400 has 24 divisors (see below), whose sum is σ = 32911101635970. Its totient is φ = 5662125012480.
The previous prime is 14155312531397. The next prime is 14155312531439. The reversal of 14155312531400 is 413521355141.
It is a happy number.
It can be written as a sum of positive squares in 3 ways, for example, as 12486343094404 + 1668969436996 = 3533602^2 + 1291886^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 35388281129 + ... + 35388281528.
Almost surely, 214155312531400 is an apocalyptic number.
14155312531400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14155312531400 is an abundant number, since it is smaller than the sum of its proper divisors (18755789104570).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14155312531400 is a wasteful number, since it uses less digits than its factorization.
14155312531400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70776562673 (or 70776562664 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 14155312531400 its reverse (413521355141), we get a palindrome (14568833886541).
The spelling of 14155312531400 in words is "fourteen trillion, one hundred fifty-five billion, three hundred twelve million, five hundred thirty-one thousand, four hundred".
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