14167311341 has 2 divisors, whose sum is σ = 14167311342. Its totient is φ = 14167311340.

The previous prime is 14167311337. The next prime is 14167311343. The reversal of 14167311341 is 14311376141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13678238116 + 489073225 = 116954^2 + 22115^2 .

It is a cyclic number.

It is not a de Polignac number, because 14167311341 - 2² = 14167311337 is a prime.

Together with 14167311343, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14167311298 and 14167311307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14167311343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7083655670 + 7083655671.

It is an arithmetic number, because the mean of its divisors is an integer number (7083655671).

Almost surely, 2^14167311341 is an apocalyptic number.

It is an amenable number.

14167311341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14167311341 is an equidigital number, since it uses as much as digits as its factorization.

14167311341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6048, while the sum is 32.

Adding to 14167311341 its reverse (14311376141), we get a palindrome (28478687482).

The spelling of 14167311341 in words is "fourteen billion, one hundred sixty-seven million, three hundred eleven thousand, three hundred forty-one".