Base | Representation |
---|---|
bin | 11010011100111010… |
… | …11100011011010111 |
3 | 1100122201010220112222 |
4 | 31032131130123113 |
5 | 213041004241401 |
6 | 10305101532555 |
7 | 1011630401561 |
oct | 151635343327 |
9 | 40581126488 |
10 | 14201243351 |
11 | 6028260359 |
12 | 2903b7415b |
13 | 1454210099 |
14 | 98a100331 |
15 | 581b35c1b |
hex | 34e75c6d7 |
14201243351 has 2 divisors, whose sum is σ = 14201243352. Its totient is φ = 14201243350.
The previous prime is 14201243341. The next prime is 14201243377. The reversal of 14201243351 is 15334210241.
It is a happy number.
It is an a-pointer prime, because the next prime (14201243377) can be obtained adding 14201243351 to its sum of digits (26).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14201243351 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14201243351.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14201243341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7100621675 + 7100621676.
It is an arithmetic number, because the mean of its divisors is an integer number (7100621676).
Almost surely, 214201243351 is an apocalyptic number.
14201243351 is a deficient number, since it is larger than the sum of its proper divisors (1).
14201243351 is an equidigital number, since it uses as much as digits as its factorization.
14201243351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 14201243351 its reverse (15334210241), we get a palindrome (29535453592).
The spelling of 14201243351 in words is "fourteen billion, two hundred one million, two hundred forty-three thousand, three hundred fifty-one".
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