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142017367421 is a prime number
BaseRepresentation
bin1000010001000011100…
…1010000110101111101
3111120120102201202121002
42010100321100311331
54311322421224141
6145124125020045
713155215463656
oct2042071206575
9446512652532
10142017367421
1155258113146
12236353b4625
131051380a427
146c3352852d
153a62db4e9b
hex2110e50d7d

142017367421 has 2 divisors, whose sum is σ = 142017367422. Its totient is φ = 142017367420.

The previous prime is 142017367409. The next prime is 142017367423. The reversal of 142017367421 is 124763710241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110748518521 + 31268848900 = 332789^2 + 176830^2 .

It is a cyclic number.

It is not a de Polignac number, because 142017367421 - 210 = 142017366397 is a prime.

Together with 142017367423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142017367423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71008683710 + 71008683711.

It is an arithmetic number, because the mean of its divisors is an integer number (71008683711).

Almost surely, 2142017367421 is an apocalyptic number.

It is an amenable number.

142017367421 is a deficient number, since it is larger than the sum of its proper divisors (1).

142017367421 is an equidigital number, since it uses as much as digits as its factorization.

142017367421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56448, while the sum is 38.

The spelling of 142017367421 in words is "one hundred forty-two billion, seventeen million, three hundred sixty-seven thousand, four hundred twenty-one".