14203511431142 has 64 divisors (see below), whose sum is σ = 24526726076160. Its totient is φ = 6101021721600.

The previous prime is 14203511431079. The next prime is 14203511431169. The reversal of 14203511431142 is 24113411530241.

It is a junction number, because it is equal to n+sod(n) for n = 14203511431099 and 14203511431108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 389151038 + ... + 389187534.

It is an arithmetic number, because the mean of its divisors is an integer number (383230094940).

Almost surely, 2^{14203511431142} is an apocalyptic number.

14203511431142 is a deficient number, since it is larger than the sum of its proper divisors (10323214645018).

14203511431142 is a wasteful number, since it uses less digits than its factorization.

14203511431142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38837.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 14203511431142 its reverse (24113411530241), we get a palindrome (38316922961383).

Subtracting 14203511431142 from its reverse (24113411530241), we obtain a palindrome (9909900099099).

The spelling of 14203511431142 in words is "fourteen trillion, two hundred three billion, five hundred eleven million, four hundred thirty-one thousand, one hundred forty-two".