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14209691 is a prime number
BaseRepresentation
bin110110001101…
…001010011011
3222201221000212
4312031022123
512114202231
61224321335
7231531446
oct66151233
928657025
1014209691
118025a51
12491324b
132c36a02
141c5c65d
1513aa42b
hexd8d29b

14209691 has 2 divisors, whose sum is σ = 14209692. Its totient is φ = 14209690.

The previous prime is 14209667. The next prime is 14209693. The reversal of 14209691 is 19690241.

It is a strong prime.

It is an emirp because it is prime and its reverse (19690241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14209691 - 218 = 13947547 is a prime.

Together with 14209693, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14209693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7104845 + 7104846.

It is an arithmetic number, because the mean of its divisors is an integer number (7104846).

Almost surely, 214209691 is an apocalyptic number.

14209691 is a deficient number, since it is larger than the sum of its proper divisors (1).

14209691 is an equidigital number, since it uses as much as digits as its factorization.

14209691 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 32.

The square root of 14209691 is about 3769.5743791574. The cubic root of 14209691 is about 242.2115662328.

It can be divided in two parts, 1420 and 9691, that added together give a palindrome (11111).

The spelling of 14209691 in words is "fourteen million, two hundred nine thousand, six hundred ninety-one".