Base | Representation |
---|---|
bin | 100000010100000000000111… |
… | …111100010111001110101110 |
3 | 200122011202221101211121001111 |
4 | 200110000013330113032232 |
5 | 122111330344323414400 |
6 | 1222125205011502234 |
7 | 41635153054634266 |
oct | 4024000774271656 |
9 | 618152841747044 |
10 | 142112011154350 |
11 | 41310402498176 |
12 | 13b32314bb797a |
13 | 613b14a023113 |
14 | 27143880c07a6 |
15 | 11669d5e293ba |
hex | 814007f173ae |
142112011154350 has 24 divisors (see below), whose sum is σ = 264701159347320. Its totient is φ = 56764628418720.
The previous prime is 142112011154329. The next prime is 142112011154363. The reversal of 142112011154350 is 53451110211241.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2004365272 + ... + 2004436171.
It is an arithmetic number, because the mean of its divisors is an integer number (11029214972805).
Almost surely, 2142112011154350 is an apocalyptic number.
142112011154350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
142112011154350 is a deficient number, since it is larger than the sum of its proper divisors (122589148192970).
142112011154350 is a wasteful number, since it uses less digits than its factorization.
142112011154350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4008802164 (or 4008802159 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 142112011154350 its reverse (53451110211241), we get a palindrome (195563121365591).
The spelling of 142112011154350 in words is "one hundred forty-two trillion, one hundred twelve billion, eleven million, one hundred fifty-four thousand, three hundred fifty".
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