Base | Representation |
---|---|
bin | 100000010100001011010100… |
… | …011001010111001101011100 |
3 | 200122012220222002202100222201 |
4 | 200110023110121113031130 |
5 | 122112030003444234400 |
6 | 1222134513440021244 |
7 | 41636056661666644 |
oct | 4024132431271534 |
9 | 618186862670881 |
10 | 142124031243100 |
11 | 4131551051a815 |
12 | 13b3470a601824 |
13 | 613c31439c57a |
14 | 2714ba864b524 |
15 | 1166e8b31706a |
hex | 8142d465735c |
142124031243100 has 18 divisors (see below), whose sum is σ = 308409147797744. Its totient is φ = 56849612497200.
The previous prime is 142124031243059. The next prime is 142124031243113. The reversal of 142124031243100 is 1342130421241.
It is a happy number.
It is a super-2 number, since 2×1421240312431002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 710620156116 + ... + 710620156315.
Almost surely, 2142124031243100 is an apocalyptic number.
142124031243100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
142124031243100 is an abundant number, since it is smaller than the sum of its proper divisors (166285116554644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
142124031243100 is a wasteful number, since it uses less digits than its factorization.
142124031243100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1421240312445 (or 1421240312438 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 142124031243100 its reverse (1342130421241), we get a palindrome (143466161664341).
The spelling of 142124031243100 in words is "one hundred forty-two trillion, one hundred twenty-four billion, thirty-one million, two hundred forty-three thousand, one hundred".
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