Base | Representation |
---|---|
bin | 1100111011010100110100… |
… | …0101011001001101110111 |
3 | 1212022210010002211222210101 |
4 | 3032311031011121031313 |
5 | 3330332410022321403 |
6 | 50121303540334531 |
7 | 2664610546653436 |
oct | 316651505311567 |
9 | 55283102758711 |
10 | 14213340042103 |
11 | 458a930a04974 |
12 | 17167829a4447 |
13 | 7c1409c22657 |
14 | 371d0211311d |
15 | 199ac559271d |
hex | ced4d159377 |
14213340042103 has 2 divisors, whose sum is σ = 14213340042104. Its totient is φ = 14213340042102.
The previous prime is 14213340042101. The next prime is 14213340042113. The reversal of 14213340042103 is 30124004331241.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14213340042103 - 21 = 14213340042101 is a prime.
Together with 14213340042101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14213340042101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106670021051 + 7106670021052.
It is an arithmetic number, because the mean of its divisors is an integer number (7106670021052).
Almost surely, 214213340042103 is an apocalyptic number.
14213340042103 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213340042103 is an equidigital number, since it uses as much as digits as its factorization.
14213340042103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 14213340042103 its reverse (30124004331241), we get a palindrome (44337344373344).
The spelling of 14213340042103 in words is "fourteen trillion, two hundred thirteen billion, three hundred forty million, forty-two thousand, one hundred three".
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