Base | Representation |
---|---|
bin | 1100111011010100110100… |
… | …0101011001001101111111 |
3 | 1212022210010002211222210200 |
4 | 3032311031011121031333 |
5 | 3330332410022321421 |
6 | 50121303540334543 |
7 | 2664610546653450 |
oct | 316651505311577 |
9 | 55283102758720 |
10 | 14213340042111 |
11 | 458a930a04981 |
12 | 17167829a4453 |
13 | 7c1409c22662 |
14 | 371d02113127 |
15 | 199ac5592726 |
hex | ced4d15937f |
14213340042111 has 24 divisors (see below), whose sum is σ = 24008949444480. Its totient is φ = 7933026998736.
The previous prime is 14213340042103. The next prime is 14213340042113. The reversal of 14213340042111 is 11124004331241.
It is a happy number.
14213340042111 is a `hidden beast` number, since 1 + 4 + 213 + 3 + 400 + 42 + 1 + 1 + 1 = 666.
It is not a de Polignac number, because 14213340042111 - 23 = 14213340042103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14213340042113) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2623352781 + ... + 2623358198.
It is an arithmetic number, because the mean of its divisors is an integer number (1000372893520).
Almost surely, 214213340042111 is an apocalyptic number.
14213340042111 is a deficient number, since it is larger than the sum of its proper divisors (9795609402369).
14213340042111 is a wasteful number, since it uses less digits than its factorization.
14213340042111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5246711035 (or 5246711032 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 14213340042111 its reverse (11124004331241), we get a palindrome (25337344373352).
The spelling of 14213340042111 in words is "fourteen trillion, two hundred thirteen billion, three hundred forty million, forty-two thousand, one hundred eleven".
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