Base | Representation |
---|---|
bin | 1000010001100001010… |
… | …1001010110100101111 |
3 | 111120220010111000111121 |
4 | 2010120111022310233 |
5 | 4312101340421221 |
6 | 145144343001411 |
7 | 13161262053526 |
oct | 2043025126457 |
9 | 446803430447 |
10 | 142142123311 |
11 | 55311583091 |
12 | 2366b139267 |
13 | 1053360ac96 |
14 | 6c45d214bd |
15 | 3a6dd09a41 |
hex | 211854ad2f |
142142123311 has 2 divisors, whose sum is σ = 142142123312. Its totient is φ = 142142123310.
The previous prime is 142142123309. The next prime is 142142123363. The reversal of 142142123311 is 113321241241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142142123311 - 21 = 142142123309 is a prime.
Together with 142142123309, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142142123371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71071061655 + 71071061656.
It is an arithmetic number, because the mean of its divisors is an integer number (71071061656).
Almost surely, 2142142123311 is an apocalyptic number.
142142123311 is a deficient number, since it is larger than the sum of its proper divisors (1).
142142123311 is an equidigital number, since it uses as much as digits as its factorization.
142142123311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1152, while the sum is 25.
Adding to 142142123311 its reverse (113321241241), we get a palindrome (255463364552).
The spelling of 142142123311 in words is "one hundred forty-two billion, one hundred forty-two million, one hundred twenty-three thousand, three hundred eleven".
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