Base | Representation |
---|---|
bin | 10100101100101000111… |
… | …101010000000101110111 |
3 | 12000222021000111100112221 |
4 | 110230220331100011313 |
5 | 141300403224222221 |
6 | 3005223322023211 |
7 | 204521306513443 |
oct | 24545075200567 |
9 | 5028230440487 |
10 | 1422321320311 |
11 | 4a922633a651 |
12 | 1ab7a4647b07 |
13 | a41801b0008 |
14 | 4cbaad0d823 |
15 | 26ee7aae541 |
hex | 14b28f50177 |
1422321320311 has 2 divisors, whose sum is σ = 1422321320312. Its totient is φ = 1422321320310.
The previous prime is 1422321320309. The next prime is 1422321320327. The reversal of 1422321320311 is 1130231232241.
It is a weak prime.
It is an emirp because it is prime and its reverse (1130231232241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1422321320311 - 21 = 1422321320309 is a prime.
It is a super-2 number, since 2×14223213203112 (a number of 25 digits) contains 22 as substring.
Together with 1422321320309, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1422321320911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711160660155 + 711160660156.
It is an arithmetic number, because the mean of its divisors is an integer number (711160660156).
Almost surely, 21422321320311 is an apocalyptic number.
1422321320311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1422321320311 is an equidigital number, since it uses as much as digits as its factorization.
1422321320311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1422321320311 its reverse (1130231232241), we get a palindrome (2552552552552).
The spelling of 1422321320311 in words is "one trillion, four hundred twenty-two billion, three hundred twenty-one million, three hundred twenty thousand, three hundred eleven".
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