1422343133501 has 2 divisors, whose sum is σ = 1422343133502. Its totient is φ = 1422343133500.

The previous prime is 1422343133399. The next prime is 1422343133503. The reversal of 1422343133501 is 1053313432241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1380143292025 + 42199841476 = 1174795^2 + 205426^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1422343133501 is a prime.

Together with 1422343133503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1422343133503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711171566750 + 711171566751.

It is an arithmetic number, because the mean of its divisors is an integer number (711171566751).

Almost surely, 2^{1422343133501} is an apocalyptic number.

It is an amenable number.

1422343133501 is a deficient number, since it is larger than the sum of its proper divisors (1).

1422343133501 is an equidigital number, since it uses as much as digits as its factorization.

1422343133501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 1422343133501 its reverse (1053313432241), we get a palindrome (2475656565742).

The spelling of 1422343133501 in words is "one trillion, four hundred twenty-two billion, three hundred forty-three million, one hundred thirty-three thousand, five hundred one".