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142252403332471 is a prime number
BaseRepresentation
bin100000010110000010110111…
…111110000001010101110111
3200122200012022120111012001021
4200112002313332001111313
5122121130410223114341
61222313504003242011
741651253110520115
oct4026026776012567
9618605276435037
10142252403332471
11413649a6194563
1213b55576079307
13614b461c18373
14271b0a5838ab5
15116a4a12b69d1
hex8160b7f81577

142252403332471 has 2 divisors, whose sum is σ = 142252403332472. Its totient is φ = 142252403332470.

The previous prime is 142252403332469. The next prime is 142252403332537. The reversal of 142252403332471 is 174233304252241.

It is a happy number.

142252403332471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142252403332471 - 21 = 142252403332469 is a prime.

It is a super-3 number, since 3×1422524033324713 (a number of 43 digits) contains 333 as substring.

Together with 142252403332469, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142252403332441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71126201666235 + 71126201666236.

It is an arithmetic number, because the mean of its divisors is an integer number (71126201666236).

Almost surely, 2142252403332471 is an apocalyptic number.

142252403332471 is a deficient number, since it is larger than the sum of its proper divisors (1).

142252403332471 is an equidigital number, since it uses as much as digits as its factorization.

142252403332471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 967680, while the sum is 43.

The spelling of 142252403332471 in words is "one hundred forty-two trillion, two hundred fifty-two billion, four hundred three million, three hundred thirty-two thousand, four hundred seventy-one".