Base | Representation |
---|---|
bin | 100000010110111001110001… |
… | …001000100000001101000110 |
3 | 200122212211110021120200120210 |
4 | 200112321301020200031012 |
5 | 122123112113134041014 |
6 | 1222400532403540250 |
7 | 41655440531622132 |
oct | 4026716110401506 |
9 | 618784407520523 |
10 | 142311344440134 |
11 | 413879a1984091 |
12 | 13b64a8538a686 |
13 | 6153b9618862c |
14 | 271dc978103c2 |
15 | 116bca0aa3859 |
hex | 816e71220346 |
142311344440134 has 64 divisors (see below), whose sum is σ = 306536586209280. Its totient is φ = 43880878594560.
The previous prime is 142311344440123. The next prime is 142311344440163. The reversal of 142311344440134 is 431044443113241.
It is a junction number, because it is equal to n+sod(n) for n = 142311344440092 and 142311344440101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26625472 + ... + 31520444.
It is an arithmetic number, because the mean of its divisors is an integer number (4789634159520).
Almost surely, 2142311344440134 is an apocalyptic number.
142311344440134 is an abundant number, since it is smaller than the sum of its proper divisors (164225241769146).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
142311344440134 is a wasteful number, since it uses less digits than its factorization.
142311344440134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4899885.
The product of its (nonzero) digits is 221184, while the sum is 39.
Adding to 142311344440134 its reverse (431044443113241), we get a palindrome (573355787553375).
The spelling of 142311344440134 in words is "one hundred forty-two trillion, three hundred eleven billion, three hundred forty-four million, four hundred forty thousand, one hundred thirty-four".
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