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142323651047 is a prime number
BaseRepresentation
bin1000010010001100100…
…1101001000111100111
3111121100210001120202002
42010203021221013213
54312434323313142
6145214345435515
713165625034104
oct2044311510747
9447323046662
10142323651047
11553a4a99606
12236bba9bb9b
13105620c8346
146c62095aab
153a7ec15a32
hex21232691e7

142323651047 has 2 divisors, whose sum is σ = 142323651048. Its totient is φ = 142323651046.

The previous prime is 142323651011. The next prime is 142323651049. The reversal of 142323651047 is 740156323241.

It is a strong prime.

It is an emirp because it is prime and its reverse (740156323241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142323651047 - 222 = 142319456743 is a prime.

Together with 142323651049, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 142323651047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142323651049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71161825523 + 71161825524.

It is an arithmetic number, because the mean of its divisors is an integer number (71161825524).

Almost surely, 2142323651047 is an apocalyptic number.

142323651047 is a deficient number, since it is larger than the sum of its proper divisors (1).

142323651047 is an equidigital number, since it uses as much as digits as its factorization.

142323651047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 38.

Adding to 142323651047 its reverse (740156323241), we get a palindrome (882479974288).

The spelling of 142323651047 in words is "one hundred forty-two billion, three hundred twenty-three million, six hundred fifty-one thousand, forty-seven".