Base | Representation |
---|---|
bin | 100000010111001111001011… |
… | …011010110001000001010000 |
3 | 200122222000210110112000112202 |
4 | 200113033023122301001100 |
5 | 122124001204001413040 |
6 | 1222415253530142332 |
7 | 41660213325024335 |
oct | 4027171332610120 |
9 | 618860713460482 |
10 | 142334334013520 |
11 | 413967199a1910 |
12 | 13b694205819a8 |
13 | 61560bb0369ac |
14 | 2721038b8698c |
15 | 116c699004015 |
hex | 8173cb6b1050 |
142334334013520 has 80 divisors (see below), whose sum is σ = 361289975479488. Its totient is φ = 51718033336320.
The previous prime is 142334334013519. The next prime is 142334334013523. The reversal of 142334334013520 is 25310433433241.
It is a tau number, because it is divible by the number of its divisors (80).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142334334013523) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61211594 + ... + 63494313.
Almost surely, 2142334334013520 is an apocalyptic number.
142334334013520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
142334334013520 is an abundant number, since it is smaller than the sum of its proper divisors (218955641465968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
142334334013520 is a wasteful number, since it uses less digits than its factorization.
142334334013520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124707228 (or 124707222 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 38.
Adding to 142334334013520 its reverse (25310433433241), we get a palindrome (167644767446761).
The spelling of 142334334013520 in words is "one hundred forty-two trillion, three hundred thirty-four billion, three hundred thirty-four million, thirteen thousand, five hundred twenty".
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