Base | Representation |
---|---|
bin | 1100111100100010111001… |
… | …1101100010100000111111 |
3 | 1212101210012220210210102112 |
4 | 3033020232131202200333 |
5 | 3331203322041130211 |
6 | 50135051521044235 |
7 | 2666252152100456 |
oct | 317105635424077 |
9 | 55353186723375 |
10 | 14234301114431 |
11 | 4598807989842 |
12 | 171a85278667b |
13 | 7c339a757a28 |
14 | 372d2dcd1b9d |
15 | 19a4008a088b |
hex | cf22e76283f |
14234301114431 has 2 divisors, whose sum is σ = 14234301114432. Its totient is φ = 14234301114430.
The previous prime is 14234301114419. The next prime is 14234301114461. The reversal of 14234301114431 is 13441110343241.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14234301114431 - 218 = 14234300852287 is a prime.
It is a super-2 number, since 2×142343011144312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14234301114461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117150557215 + 7117150557216.
It is an arithmetic number, because the mean of its divisors is an integer number (7117150557216).
Almost surely, 214234301114431 is an apocalyptic number.
14234301114431 is a deficient number, since it is larger than the sum of its proper divisors (1).
14234301114431 is an equidigital number, since it uses as much as digits as its factorization.
14234301114431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 14234301114431 its reverse (13441110343241), we get a palindrome (27675411457672).
The spelling of 14234301114431 in words is "fourteen trillion, two hundred thirty-four billion, three hundred one million, one hundred fourteen thousand, four hundred thirty-one".
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