Base | Representation |
---|---|
bin | 1100111101000000000011… |
… | …0001001000001011101111 |
3 | 1212102112102010202111202012 |
4 | 3033100000301020023233 |
5 | 3331320332323311421 |
6 | 50142424105551435 |
7 | 2666650056151022 |
oct | 317200061101357 |
9 | 55375363674665 |
10 | 14242124432111 |
11 | 45a1061a50144 |
12 | 17202767a557b |
13 | 7c40464b90a4 |
14 | 373472d271b9 |
15 | 19a70c5ea95b |
hex | cf400c482ef |
14242124432111 has 2 divisors, whose sum is σ = 14242124432112. Its totient is φ = 14242124432110.
The previous prime is 14242124432099. The next prime is 14242124432197. The reversal of 14242124432111 is 11123442124241.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (11123442124241) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14242124432111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14242124432311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121062216055 + 7121062216056.
It is an arithmetic number, because the mean of its divisors is an integer number (7121062216056).
Almost surely, 214242124432111 is an apocalyptic number.
14242124432111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14242124432111 is an equidigital number, since it uses as much as digits as its factorization.
14242124432111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12288, while the sum is 32.
Adding to 14242124432111 its reverse (11123442124241), we get a palindrome (25365566556352).
The spelling of 14242124432111 in words is "fourteen trillion, two hundred forty-two billion, one hundred twenty-four million, four hundred thirty-two thousand, one hundred eleven".
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