14243313101999 has 2 divisors, whose sum is σ = 14243313102000. Its totient is φ = 14243313101998.

The previous prime is 14243313101929. The next prime is 14243313102001. The reversal of 14243313101999 is 99910131334241.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14243313101999 is a prime.

Together with 14243313102001, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14243313101929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121656550999 + 7121656551000.

It is an arithmetic number, because the mean of its divisors is an integer number (7121656551000).

Almost surely, 2^{14243313101999} is an apocalyptic number.

14243313101999 is a deficient number, since it is larger than the sum of its proper divisors (1).

14243313101999 is an equidigital number, since it uses as much as digits as its factorization.

14243313101999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 629856, while the sum is 50.

The spelling of 14243313101999 in words is "fourteen trillion, two hundred forty-three billion, three hundred thirteen million, one hundred one thousand, nine hundred ninety-nine".