Search a number
-
+
14251387041737 is a prime number
BaseRepresentation
bin1100111101100010100011…
…0111001011011111001001
31212110102022122222211102222
43033120220313023133021
53331443320040313422
650150555151503425
73000425441062556
oct317305067133711
955412278884388
1014251387041737
1145a4a854a791a
121722020827b75
137c4b914a53a1
14373ab117ba2d
1519aaa089c842
hexcf628dcb7c9

14251387041737 has 2 divisors, whose sum is σ = 14251387041738. Its totient is φ = 14251387041736.

The previous prime is 14251387041707. The next prime is 14251387041739. The reversal of 14251387041737 is 73714078315241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10256749243456 + 3994637798281 = 3202616^2 + 1998659^2 .

It is a cyclic number.

It is not a de Polignac number, because 14251387041737 - 210 = 14251387040713 is a prime.

It is a super-2 number, since 2×142513870417372 (a number of 27 digits) contains 22 as substring.

Together with 14251387041739, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14251387041739) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7125693520868 + 7125693520869.

It is an arithmetic number, because the mean of its divisors is an integer number (7125693520869).

Almost surely, 214251387041737 is an apocalyptic number.

It is an amenable number.

14251387041737 is a deficient number, since it is larger than the sum of its proper divisors (1).

14251387041737 is an equidigital number, since it uses as much as digits as its factorization.

14251387041737 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3951360, while the sum is 53.

The spelling of 14251387041737 in words is "fourteen trillion, two hundred fifty-one billion, three hundred eighty-seven million, forty-one thousand, seven hundred thirty-seven".