Base | Representation |
---|---|
bin | 1100111101110000111011… |
… | …0000101111101001110110 |
3 | 1212110210021110202102122121 |
4 | 3033130032300233221312 |
5 | 3332024214443131200 |
6 | 50152434014150154 |
7 | 3000623144465035 |
oct | 317341660575166 |
9 | 55423243672577 |
10 | 14255244114550 |
11 | 45a668473a7aa |
12 | 17229184b235a |
13 | 7c53576032aa |
14 | 373d5952871c |
15 | 19ac292dde1a |
hex | cf70ec2fa76 |
14255244114550 has 24 divisors (see below), whose sum is σ = 26723531655936. Its totient is φ = 5657199236640.
The previous prime is 14255244114523. The next prime is 14255244114569. The reversal of 14255244114550 is 5541144255241.
It is a junction number, because it is equal to n+sod(n) for n = 14255244114497 and 14255244114506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1122453817 + ... + 1122466516.
It is an arithmetic number, because the mean of its divisors is an integer number (1113480485664).
Almost surely, 214255244114550 is an apocalyptic number.
14255244114550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14255244114550 is a deficient number, since it is larger than the sum of its proper divisors (12468287541386).
14255244114550 is a wasteful number, since it uses less digits than its factorization.
14255244114550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2244920472 (or 2244920467 counting only the distinct ones).
The product of its (nonzero) digits is 640000, while the sum is 43.
Adding to 14255244114550 its reverse (5541144255241), we get a palindrome (19796388369791).
The spelling of 14255244114550 in words is "fourteen trillion, two hundred fifty-five billion, two hundred forty-four million, one hundred fourteen thousand, five hundred fifty".
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