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143112300 = 223523712893
BaseRepresentation
bin10001000011110…
…11100001101100
3100222021212011120
420201323201230
5243114043200
622111220540
73355302012
oct1041734154
9328255146
10143112300
1173868431
123bb17750
1323859b46
14150148b2
15c86d9a0
hex887b86c

143112300 has 72 divisors (see below), whose sum is σ = 425295696. Its totient is φ = 37128960.

The previous prime is 143112287. The next prime is 143112311. The reversal of 143112300 is 3211341.

It is a super-2 number, since 2×1431123002 = 40962260822580000, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 143112300.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4654 + ... + 17546.

Almost surely, 2143112300 is an apocalyptic number.

143112300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 143112300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (212647848).

143112300 is an abundant number, since it is smaller than the sum of its proper divisors (282183396).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143112300 is a wasteful number, since it uses less digits than its factorization.

143112300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12947 (or 12940 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 143112300 is about 11962.9553204883. The cubic root of 143112300 is about 523.0690061241.

Adding to 143112300 its reverse (3211341), we get a palindrome (146323641).

It can be divided in two parts, 1431 and 12300, that added together give a palindrome (13731).

The spelling of 143112300 in words is "one hundred forty-three million, one hundred twelve thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 37 50 60 74 75 100 111 148 150 185 222 300 370 444 555 740 925 1110 1850 2220 2775 3700 5550 11100 12893 25786 38679 51572 64465 77358 128930 154716 193395 257860 322325 386790 477041 644650 773580 954082 966975 1289300 1431123 1908164 1933950 2385205 2862246 3867900 4770410 5724492 7155615 9540820 11926025 14311230 23852050 28622460 35778075 47704100 71556150 143112300