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1431221444413 is a prime number
BaseRepresentation
bin10100110100111011011…
…100100001111100111101
312001211020021122111120221
4110310323130201330331
5141422120142210123
63013254414341341
7205255000360225
oct24647334417475
95054207574527
101431221444413
11501a83214612
121b14691ba851
13a4c6b061137
144d3b2d67085
152736910d25d
hex14d3b721f3d

1431221444413 has 2 divisors, whose sum is σ = 1431221444414. Its totient is φ = 1431221444412.

The previous prime is 1431221444377. The next prime is 1431221444449. The reversal of 1431221444413 is 3144441221341.

It is a balanced prime because it is at equal distance from previous prime (1431221444377) and next prime (1431221444449).

It can be written as a sum of positive squares in only one way, i.e., 1238976026649 + 192245417764 = 1113093^2 + 438458^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431221444413 - 237 = 1293782490941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1431221444453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715610722206 + 715610722207.

It is an arithmetic number, because the mean of its divisors is an integer number (715610722207).

Almost surely, 21431221444413 is an apocalyptic number.

It is an amenable number.

1431221444413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431221444413 is an equidigital number, since it uses as much as digits as its factorization.

1431221444413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36864, while the sum is 34.

Adding to 1431221444413 its reverse (3144441221341), we get a palindrome (4575662665754).

The spelling of 1431221444413 in words is "one trillion, four hundred thirty-one billion, two hundred twenty-one million, four hundred forty-four thousand, four hundred thirteen".