Base | Representation |
---|---|
bin | 100000100010110000110100… |
… | …000010011010100001010010 |
3 | 200202202202011100012111110102 |
4 | 200202300310002122201102 |
5 | 122224440242441020200 |
6 | 1224223202112532402 |
7 | 42101352464141420 |
oct | 4042606402324122 |
9 | 622682140174412 |
10 | 143126363220050 |
11 | 41671605817491 |
12 | 14076a21551102 |
13 | 61b29b1828012 |
14 | 274b4d2688110 |
15 | 11830a26696d5 |
hex | 822c3409a852 |
143126363220050 has 24 divisors (see below), whose sum is σ = 304245754959936. Its totient is φ = 49071895961040.
The previous prime is 143126363220047. The next prime is 143126363220079. The reversal of 143126363220050 is 50022363621341.
It is a junction number, because it is equal to n+sod(n) for n = 143126363219986 and 143126363220013.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 204466232822 + ... + 204466233521.
It is an arithmetic number, because the mean of its divisors is an integer number (12676906456664).
Almost surely, 2143126363220050 is an apocalyptic number.
143126363220050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
143126363220050 is an abundant number, since it is smaller than the sum of its proper divisors (161119391739886).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143126363220050 is a wasteful number, since it uses less digits than its factorization.
143126363220050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 408932466362 (or 408932466357 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 38.
The spelling of 143126363220050 in words is "one hundred forty-three trillion, one hundred twenty-six billion, three hundred sixty-three million, two hundred twenty thousand, fifty".
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