Base | Representation |
---|---|
bin | 100000100010110101100000… |
… | …011111100010100110000100 |
3 | 200202210020011122100200011120 |
4 | 200202311200133202212010 |
5 | 122230031103412120400 |
6 | 1224225354222433540 |
7 | 42101621423215446 |
oct | 4042654037424604 |
9 | 622706148320146 |
10 | 143131404020100 |
11 | 41673762161141 |
12 | 140779a97328b0 |
13 | 61b3305c70642 |
14 | 274b84dd2a496 |
15 | 1183299e7eca0 |
hex | 822d607e2984 |
143131404020100 has 72 divisors (see below), whose sum is σ = 414130756206048. Its totient is φ = 38168015520000.
The previous prime is 143131404020063. The next prime is 143131404020131. The reversal of 143131404020100 is 1020404131341.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 30511767 + ... + 34888833.
Almost surely, 2143131404020100 is an apocalyptic number.
143131404020100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
143131404020100 is an abundant number, since it is smaller than the sum of its proper divisors (270999352185948).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143131404020100 is a wasteful number, since it uses less digits than its factorization.
143131404020100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4486085 (or 4486078 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 143131404020100 its reverse (1020404131341), we get a palindrome (144151808151441).
The spelling of 143131404020100 in words is "one hundred forty-three trillion, one hundred thirty-one billion, four hundred four million, twenty thousand, one hundred".
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