143132100566240 has 48 divisors (see below), whose sum is σ = 338182766128368. Its totient is φ = 57247222695936.

The previous prime is 143132100566237. The next prime is 143132100566269. The reversal of 143132100566240 is 42665001231341.

It is a junction number, because it is equal to n+sod(n) for n = 143132100566194 and 143132100566203.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42250982 + ... + 45512741.

It is an arithmetic number, because the mean of its divisors is an integer number (7045474294341).

Almost surely, 2^{143132100566240} is an apocalyptic number.

143132100566240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

143132100566240 is an abundant number, since it is smaller than the sum of its proper divisors (195050665562128).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143132100566240 is a wasteful number, since it uses less digits than its factorization.

143132100566240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87773931 (or 87773923 counting only the distinct ones).

The product of its (nonzero) digits is 103680, while the sum is 38.

Adding to 143132100566240 its reverse (42665001231341), we get a palindrome (185797101797581).

The spelling of 143132100566240 in words is "one hundred forty-three trillion, one hundred thirty-two billion, one hundred million, five hundred sixty-six thousand, two hundred forty".