143134121309 has 2 divisors, whose sum is σ = 143134121310. Its totient is φ = 143134121308.

The previous prime is 143134121303. The next prime is 143134121311. The reversal of 143134121309 is 903121431341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139509720100 + 3624401209 = 373510^2 + 60203^2 .

It is a cyclic number.

It is not a de Polignac number, because 143134121309 - 2⁴ = 143134121293 is a prime.

Together with 143134121311, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143134121303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71567060654 + 71567060655.

It is an arithmetic number, because the mean of its divisors is an integer number (71567060655).

Almost surely, 2^143134121309 is an apocalyptic number.

It is an amenable number.

143134121309 is a deficient number, since it is larger than the sum of its proper divisors (1).

143134121309 is an equidigital number, since it uses as much as digits as its factorization.

143134121309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 32.

The spelling of 143134121309 in words is "one hundred forty-three billion, one hundred thirty-four million, one hundred twenty-one thousand, three hundred nine".