Search a number
-
+
143141101111 is a prime number
BaseRepresentation
bin1000010101001111011…
…1111101111000110111
3111200110202020100102101
42011103313331320313
54321123110213421
6145431430322531
713225112166331
oct2052367757067
9450422210371
10143141101111
1155784468978
12238a97b9447
131066257aac8
146cdc884451
153acb888191
hex2153dfde37

143141101111 has 2 divisors, whose sum is σ = 143141101112. Its totient is φ = 143141101110.

The previous prime is 143141101109. The next prime is 143141101127. The reversal of 143141101111 is 111101141341.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (111101141341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143141101111 - 21 = 143141101109 is a prime.

Together with 143141101109, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143141104111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71570550555 + 71570550556.

It is an arithmetic number, because the mean of its divisors is an integer number (71570550556).

Almost surely, 2143141101111 is an apocalyptic number.

143141101111 is a deficient number, since it is larger than the sum of its proper divisors (1).

143141101111 is an equidigital number, since it uses as much as digits as its factorization.

143141101111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 143141101111 its reverse (111101141341), we get a palindrome (254242242452).

The spelling of 143141101111 in words is "one hundred forty-three billion, one hundred forty-one million, one hundred one thousand, one hundred eleven".