1431412111 has 2 divisors, whose sum is σ = 1431412112. Its totient is φ = 1431412110.

The previous prime is 1431412109. The next prime is 1431412133. The reversal of 1431412111 is 1112141341.

It is a weak prime.

It is an emirp because it is prime and its reverse (1112141341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1431412111 - 2¹ = 1431412109 is a prime.

Together with 1431412109, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1431412141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715706055 + 715706056.

It is an arithmetic number, because the mean of its divisors is an integer number (715706056).

Almost surely, 2^1431412111 is an apocalyptic number.

1431412111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431412111 is an equidigital number, since it uses as much as digits as its factorization.

1431412111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 96, while the sum is 19.

The square root of 1431412111 is about 37834.0073346718. The cubic root of 1431412111 is about 1126.9938924508.

Adding to 1431412111 its reverse (1112141341), we get a palindrome (2543553452).

The spelling of 1431412111 in words is "one billion, four hundred thirty-one million, four hundred twelve thousand, one hundred eleven".