Base | Representation |
---|---|
bin | 11010101010011001… |
… | …11010111100010111 |
3 | 1100221120222110000021 |
4 | 31111030322330113 |
5 | 213303433234112 |
6 | 10324222130011 |
7 | 1014502662565 |
oct | 152514727427 |
9 | 40846873007 |
10 | 14314352407 |
11 | 6086095913 |
12 | 2935a20907 |
13 | 1471793614 |
14 | 99b144a35 |
15 | 58ba29907 |
hex | 35533af17 |
14314352407 has 2 divisors, whose sum is σ = 14314352408. Its totient is φ = 14314352406.
The previous prime is 14314352399. The next prime is 14314352441. The reversal of 14314352407 is 70425341341.
It is an a-pointer prime, because the next prime (14314352441) can be obtained adding 14314352407 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14314352407 - 23 = 14314352399 is a prime.
It is a super-3 number, since 3×143143524073 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14314352447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157176203 + 7157176204.
It is an arithmetic number, because the mean of its divisors is an integer number (7157176204).
Almost surely, 214314352407 is an apocalyptic number.
14314352407 is a deficient number, since it is larger than the sum of its proper divisors (1).
14314352407 is an equidigital number, since it uses as much as digits as its factorization.
14314352407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 14314352407 its reverse (70425341341), we get a palindrome (84739693748).
The spelling of 14314352407 in words is "fourteen billion, three hundred fourteen million, three hundred fifty-two thousand, four hundred seven".
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