14343540941 has 2 divisors, whose sum is σ = 14343540942. Its totient is φ = 14343540940.

The previous prime is 14343540919. The next prime is 14343540973. The reversal of 14343540941 is 14904534341.

It is a happy number.

14343540941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9301830916 + 5041710025 = 96446^2 + 71005^2 .

It is an emirp because it is prime and its reverse (14904534341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14343540941 - 2¹⁸ = 14343278797 is a prime.

It is a super-2 number, since 2×14343540941² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14343540895 and 14343540904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14343560941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171770470 + 7171770471.

It is an arithmetic number, because the mean of its divisors is an integer number (7171770471).

Almost surely, 2^14343540941 is an apocalyptic number.

It is an amenable number.

14343540941 is a deficient number, since it is larger than the sum of its proper divisors (1).

14343540941 is an equidigital number, since it uses as much as digits as its factorization.

14343540941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 38.

The spelling of 14343540941 in words is "fourteen billion, three hundred forty-three million, five hundred forty thousand, nine hundred forty-one".