14401011300 has 72 divisors (see below), whose sum is σ = 44872086336. Its totient is φ = 3544863360.

The previous prime is 14401011299. The next prime is 14401011307. The reversal of 14401011300 is 311010441.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 14401011300.

It is not an unprimeable number, because it can be changed into a prime (14401011307) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1842384 + ... + 1850183.

Almost surely, 2^14401011300 is an apocalyptic number.

14401011300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14401011300 is an abundant number, since it is smaller than the sum of its proper divisors (30471075036).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14401011300 is a wasteful number, since it uses less digits than its factorization.

14401011300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3692597 (or 3692590 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 14401011300 its reverse (311010441), we get a palindrome (14712021741).

The spelling of 14401011300 in words is "fourteen billion, four hundred one million, eleven thousand, three hundred".