Base | Representation |
---|---|
bin | 10100111101001101111… |
… | …110010000100001101101 |
3 | 12002200012121000021010221 |
4 | 110331031332100201231 |
5 | 142043332241213123 |
6 | 3021325532531341 |
7 | 206021366546305 |
oct | 24751576204155 |
9 | 5080177007127 |
10 | 1440122210413 |
11 | 505830497877 |
12 | 1b3132020b51 |
13 | a5a590a8493 |
14 | 4d9b910a605 |
15 | 276da73725d |
hex | 14f4df9086d |
1440122210413 has 2 divisors, whose sum is σ = 1440122210414. Its totient is φ = 1440122210412.
The previous prime is 1440122210407. The next prime is 1440122210419. The reversal of 1440122210413 is 3140122210441.
It is a balanced prime because it is at equal distance from previous prime (1440122210407) and next prime (1440122210419).
It can be written as a sum of positive squares in only one way, i.e., 1058620805449 + 381501404964 = 1028893^2 + 617658^2 .
It is a cyclic number.
It is not a de Polignac number, because 1440122210413 - 213 = 1440122202221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1440122210419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720061105206 + 720061105207.
It is an arithmetic number, because the mean of its divisors is an integer number (720061105207).
Almost surely, 21440122210413 is an apocalyptic number.
It is an amenable number.
1440122210413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1440122210413 is an equidigital number, since it uses as much as digits as its factorization.
1440122210413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1440122210413 its reverse (3140122210441), we get a palindrome (4580244420854).
The spelling of 1440122210413 in words is "one trillion, four hundred forty billion, one hundred twenty-two million, two hundred ten thousand, four hundred thirteen".
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