1440130121 has 2 divisors, whose sum is σ = 1440130122. Its totient is φ = 1440130120.

The previous prime is 1440130103. The next prime is 1440130123. The reversal of 1440130121 is 1210310441.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1439140096 + 990025 = 37936^2 + 995^2 .

It is a cyclic number.

It is not a de Polignac number, because 1440130121 - 2¹⁸ = 1439867977 is a prime.

It is a super-2 number, since 2×1440130121² = 4147949530822949282, which contains 22 as substring.

Together with 1440130123, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1440130121.

It is not a weakly prime, because it can be changed into another prime (1440130123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 720065060 + 720065061.

It is an arithmetic number, because the mean of its divisors is an integer number (720065061).

Almost surely, 2^1440130121 is an apocalyptic number.

It is an amenable number.

1440130121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1440130121 is an equidigital number, since it uses as much as digits as its factorization.

1440130121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1440130121 is about 37949.0463780053. The cubic root of 1440130121 is about 1129.2772471186.

Adding to 1440130121 its reverse (1210310441), we get a palindrome (2650440562).

The spelling of 1440130121 in words is "one billion, four hundred forty million, one hundred thirty thousand, one hundred twenty-one".