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144013151 is a prime number
BaseRepresentation
bin10001001010101…
…11011101011111
3101000222121220102
420211113131133
5243331410101
622142411315
73366043262
oct1045273537
9330877812
10144013151
1174323237
1240290b3b
1323ab3ba9
14151aacd9
15c99a86b
hex895775f

144013151 has 2 divisors, whose sum is σ = 144013152. Its totient is φ = 144013150.

The previous prime is 144013081. The next prime is 144013153. The reversal of 144013151 is 151310441.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (151310441) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 144013151 - 226 = 76904287 is a prime.

Together with 144013153, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (144013153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 72006575 + 72006576.

It is an arithmetic number, because the mean of its divisors is an integer number (72006576).

Almost surely, 2144013151 is an apocalyptic number.

144013151 is a deficient number, since it is larger than the sum of its proper divisors (1).

144013151 is an equidigital number, since it uses as much as digits as its factorization.

144013151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 144013151 is about 12000.5479458231. The cubic root of 144013151 is about 524.1642345459.

Adding to 144013151 its reverse (151310441), we get a palindrome (295323592).

The spelling of 144013151 in words is "one hundred forty-four million, thirteen thousand, one hundred fifty-one".