Base | Representation |
---|---|
bin | 10101000001001111100… |
… | …001001111000110110111 |
3 | 12010002100201120102111002 |
4 | 111001033201033012313 |
5 | 142131204414433101 |
6 | 3023322405033515 |
7 | 206233434655406 |
oct | 25011741170667 |
9 | 5102321512432 |
10 | 1444443124151 |
11 | 50764853a265 |
12 | 1b3b390b589b |
13 | a629733ac81 |
14 | 4dca8d1963d |
15 | 2788ec4cd6b |
hex | 1504f84f1b7 |
1444443124151 has 2 divisors, whose sum is σ = 1444443124152. Its totient is φ = 1444443124150.
The previous prime is 1444443124079. The next prime is 1444443124153. The reversal of 1444443124151 is 1514213444441.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1444443124151 - 226 = 1444376015287 is a prime.
Together with 1444443124153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1444443124153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 722221562075 + 722221562076.
It is an arithmetic number, because the mean of its divisors is an integer number (722221562076).
Almost surely, 21444443124151 is an apocalyptic number.
1444443124151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1444443124151 is an equidigital number, since it uses as much as digits as its factorization.
1444443124151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 122880, while the sum is 38.
Adding to 1444443124151 its reverse (1514213444441), we get a palindrome (2958656568592).
The spelling of 1444443124151 in words is "one trillion, four hundred forty-four billion, four hundred forty-three million, one hundred twenty-four thousand, one hundred fifty-one".
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